Let the mass of KClO3 be x gram
Reaction of decomposition is given by:
2KClO3→2KCl+3O2
2 moles of Potassium trioxochlorate produces 2 moles of Potassium chloride
So,
122.5x Moles will produce same amount of KCl
122.5x mole KCl=122.5x×74.5 g KCl
Now final mass =initial mass of KCl +mass of KCl produced due to decomposition = 28.9 g
So,
39.8−x +122.574.5x=28.9
0.391836x=10.9x=27.8177 g
Initial masso f Potassium chloride = 38.9−x=11.0823 g KCl
Percentage composition of KCl = 39.811.0823×100=27.844%
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