Question

determine the oxidation states of the elements in the compounds listed. none of the oxygen-containing compounds are peroxide’s or superoxides.
a.H2SO4
b.Mg(OH)2
c.P4O6

Answer 1

For $H_2So_4$ :

$Oxidation$ state of Hydrogen = $+1$

Oxidation state of oxygen = $-2$

And,

$({(1×2)+(-2×4)})+O.S.\ of \ S=0\\so,\\ oxidation\ state\ of\ sulphur=+6$

For $Mg(OH)_2:$

Oxidation state of Oxygen $=-2$

Oxidation state of hydrogen $=+1$

And,

$O.S.\ of\ Mg+(2×-1)=0\\$

So,

Oxidation state of magnesium $=+2$

For $P_4O_6:$

Oxidation state of Oxygen $=-2$

And ,

$4\times O.S.\ of\ P+(-2×6)=0$

So,

Oxidation state of phosphorus $=+3$