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Answer to Question #95622 in Physical Chemistry for m

Question #95622
What is the maximum mass of S8 that can be produced by combining 79.0 g of each reactant?

8SO2+16H2S⟶3S8+16H2O
1
Expert's answer
2019-10-04T04:35:36-0400

m(SO2) = 79g

m(H2S) = 79g

n(SO2) = 1.234 mol

n(H2S) = 2.324 mol

H2S is limiting reactant, then

nmax(S8) = 4.358 mol

m(S8) =111.55 g




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