"Reaction\\ is\\\\2C_2H_6(g) + 7O_2(g) \u2192 4CO_2(g) + 6H_2O(l)\\\\"
2 moles ethane produces 4 moles of Carbon dioxide
So "5.65" moles of ethane will produce "\\frac{4}{2}\\times 5.645=11.3\\ moles\\ CO_2"
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