Question

How many grams of a 26.8% sugar solution contain 29.5 g of sugar?

Answer 1

Solution.

$w = \frac{m(sugar)}{m(solution)} \times 100 \%$

$m(solution) = \frac{m(sugar)}{w} \times 100 \%$

m(solution) = 110.08 g

Answer:

m(solution) = 110.08 g