Answer to Question #94941 in Physical Chemistry for mya

Question

calculate the molarity of 32.9g of MgS in 981 mL of solution.

Answer 1

m(MgS) = 32.9 g

V(solution) = 981 ml = 0.981 l

n(MgS) = 32.9/56 = 0,5875 mol

M(MgS) = 0,5875 mol/0.981 l = 0,599 mol/l