Moles of "CuNO_3=\\frac{mass}{molar\\ mass}=\\frac{2.61}{125.55}=0.02078\\ mole"
Molarity = "\\frac{moles}{volume(in\\ l)}=0.480=\\frac{0.02078}{volume(in\\ l)}"
volume = "\\frac{0.02078}{0.480}=0.0433\\ l"
volume"=43.3\\ ml"
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