Moles of CuNO3=massmolar mass=2.61125.55=0.02078 moleCuNO_3=\frac{mass}{molar\ mass}=\frac{2.61}{125.55}=0.02078\ moleCuNO3=molar massmass=125.552.61=0.02078 mole
Molarity = molesvolume(in l)=0.480=0.02078volume(in l)\frac{moles}{volume(in\ l)}=0.480=\frac{0.02078}{volume(in\ l)}volume(in l)moles=0.480=volume(in l)0.02078
volume = 0.020780.480=0.0433 l\frac{0.02078}{0.480}=0.0433\ l0.4800.02078=0.0433 l
volume=43.3 ml=43.3\ ml=43.3 ml
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