Answer to Question #94883 in Physical Chemistry for Mya

Question #94883

what is the mass, in grams, of 9.08 x 10^24 molecules of methanol (CH3OH)?

Expert's answer

N(CH3OH) = 9.08 x 10^24

m (CH3OH) = n*M = (N/N_A)*M = (9.08 x 10²⁴/6.02*10²³)*32 g/mol = 482.658 g

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