Question

An oxide of antimony is found to contain 24.73% oxygen. What is the empirical formula?

Answer 1

$\frac{24.73}{M_O}:\frac{100-24.73}{M_{Sb}}=\frac{24.73}{16.00}:\frac{75.27}{12.176}=1.55:0.62=5:2$

Sb₂O₅