Answer to Question #93661 in Physical Chemistry for Raj

Question #93661
The degree of ionisation of a 0.1M bromoacetic acid solution is 0.123. Calculate the pH of the solution and the of bromoacetic acid.
1
Expert's answer
2019-09-03T02:33:26-0400

   BrCH2COOHBrCH2COO+H+\space \space \space BrCH_2COOH \to BrCH_2COO^- +H^+

at t=0 c 0 0

at t=T c(1α)c(1-\alpha) cαc \alpha cαc\alpha

Concentration of H+H^+ is given by cαc \alpha

Where α\alpha is the degree of ionisation.

[H+]=cα=0.1×0.123=1.23×102[H^+]=c \alpha =0.1 \times 0.123=1.23 \times 10^{-2} M

pH=log[H+]=log[1.23×102]=1.91pH=-log[H^+]=-log[1.23 \times 10^{-2}]=1.91


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