Solution.
Q(solution)=(m(acid)+m(hydroxide))×c(H2O)×(t2−t1)m(acid)=C(acid)×V(acid)×M(acid)m(hydroxide)=C(hydroxide)×V(hydroxide)×M(hydroxide)Q(solution) = (14.7+12)*4.18*(34.06-19.67) = 1606.01 J
Q(reaction)=−Q(solution)
ΔH=n(lim)Q(reaction)n(lim) is the limiting reagent in the reaction.
n(acid) = 0.15 mole
n(hydroxide) = 0.3 mole
Acid is limiting reagent.
ΔH=0.15−1606.01
ΔH=−10706.73JAnswer:
ΔH=−10706.73J
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