Answer to Question #90059 in Physical Chemistry for Emmaline Polinsky

Question #90059

How many grams of potassium carbonate does 1.6L of a .29M solution contain?

Expert's answer

c(K₂CO₃) = 0.29M = 0.29 mol/dm³

V(K2CO3) = 1.6 dm³

n(K2CO3) = cV = 1.6 * 0.29 = 0.464 mol

m(K2CO3) = n/M = 0.464*138 = 64.032 g

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