Question

Calculate the specific heat capacity of titanium if a 45 g sample absorbs 476 J as its temperature changes from 20⁰C to 40.25⁰C. _ J/g ⁰C (2 decimals)

Answer 1

Solution.

$$Q = c \times m \times \Delta t$$

$$Q = c \times m \times (t2-t1)$$

$$c = \frac{Q}{m \times \Delta t}$$

$$c = \frac{476}{45 \times (40.25-20)}$$

c = 0.52 J/g ⁰C

Answer:

c = 0.52 J/g ⁰C