Answer to Question #89660 in Physical Chemistry for jason

Question

Calculate the mass of gold as -3000J of energy is released as melted gold cools from 1064 ⁰C to room temperature (23⁰C) _ grams ( 2 Decimals) (Csp Au= 0.129)

Answer 1

Solution.

$$Q = c \times m \times (t2-t1)$$

$$m = \frac{Q}{c\times(t2-t1)}$$ $$m = \frac{-3000}{0.129\times10^3\times(23-1064)}$$

m = 0.02234 kg = 22.34 g

Answer:

m = 22.34 g