Question

A 40.0 g sample of ethanol (Csp = 2.46 J/g °C) releases 2952 J as it cools from 50.0 °C. Calculate the change in temperature of the ethanol. _ °C

Answer 1

Solution.

$$Q = c \times m \times \Delta t = c \times m \times (t2-t1)$$

$$\Delta t = \frac{Q}{c \times m}$$

$$\Delta t = \frac{2952}{2.46\times40} = 30$$

$$\Delta t = t2-t1$$

$$t2 = \Delta t + t1$$

t2 = 30 + 50 = 80

Answer:

t2 = 80