Cl2 + PCl3 = PCl5
2 mol Cl2 + 2 mol PCl3 = 2 mol PCl5
So, final
Cl2 = 3 mol;
N2 = 2 mol;
PCl3 = 0 mol;
PCl5 = 3 mol
Total = 8 mol;
X(PCl5) = 3*100/8 = 37,5 %
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