Answer to Question #89175 in Physical Chemistry for Ravi

Question #89175

Kp for N2O4<------>2NO2 at equilibrium pressure 3Po is 0.5Po on halving the volume of container equilibrium is distributed the new equilibrium pressure will be?

Expert's answer

N2O4 = 2 NO2

Kp = 0.5^2/3 = 0.083

P = 1/V

P2 = 2*P1

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