Answer to Question #88250 in Physical Chemistry for Roland

Question

52.7 mL of 0.1032 M dimethylamine ((CH3)2NH) is titrated with 0.0532 M HClO3. Determine the pH of the titrated solution after 34.7 mL HClO3 has been added. The base-dissociation constant for dimethylamine at 25°C is 5.4 ✕ 10−4.

Answer 1

(CH₃)₂NH + H⁺ = (CH₃)₂NH₂⁺

C1V1=C2V2

52.7*0.1032 = 5.44 mol;

34.7*0.0532 = 1.85 mol;(CH₃)₂NH + H⁺ = (CH₃)₂NH₂⁺

C1V1=C2V2

52.7*0.1032 = 5.44 mol;

34.7*0.0532 = 1.85 mol;