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Answer to Question #87258 in Physical Chemistry for Anand
Question #87258
The net energy of a system of two atoms is given by
E(r)=-A/r^2 + B/r^8
where r is
the inter-atomic separation. If in a stable molecule the interatomic separation is 0.5
nm and the dissociation energy is 4.0eV, calculate the constants A and B.
E(r)=-A/r^2 + B/r^8
where r is
the inter-atomic separation. If in a stable molecule the interatomic separation is 0.5
nm and the dissociation energy is 4.0eV, calculate the constants A and B.
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