Question #81531

The complete mechanism for a reaction is considered to occur in two steps, one of which is slow and the other fast.


A + B → C + D slow


A + C → E + F fast


The stoichiometric equation for the reaction is:
2A + B = D + E + F
A + B + C = D + E + F
A + B = C + D
A + B = D + E + F
A + C = E + F

Expert's answer

The complete mechanism for a reaction is considered to occur in two steps, one of which is slow and the other fast.


A+BC+D slowA + B \rightarrow C + D \text{ slow}A+CE+F fastA + C \rightarrow E + F \text{ fast}


The stoichiometric equation for the reaction is:


2A+B=D+E+F2A + B = D + E + FA+B+C=D+E+FA + B + C = D + E + FA+B=C+DA + B = C + DA+B=D+E+FA + B = D + E + FA+C=E+FA + C = E + F


Solution:

The stoichiometric equation for the reaction is A+B+C=D+E+FA + B + C = D + E + F

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