Answer to Question #7953 in Physical Chemistry for Kester Chase
CaC12(aq)+Na2CO3(aq) > CaCO3(s)+ 2NaC1(aq)
how many moles of sodium carbonate were initially present? 1.06g of sodium carbonate
1
2012-04-12T09:54:48-0400
n=m/Mr
n=1.06/(23*2+12+16*3)=1.06/106=0,01 mol
Need a fast expert's response?
Submit order
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment