Answer on Question #78557 - Chemistry - Physical Chemistry
Question: A reaction is catalyzed by an enzyme with parameters k=103 s-1, KM=61·10-6 M and concentration [E]0= 3.5·10-6 M. The initial concentration of the substrate is [S]0= 3.6·10-5 M. Estimate initial reaction rate. Find the substrate's concentration providing 2-fold decreasing of the reaction rate.
Solution:
v0=[zˉ]s+Kmk⋅[xˉ]s⋅[zˉ]s,v0=103⋅3.5⋅10−6⋅3.6⋅10−5/(3.6⋅10−5+61⋅10−6)=1.3⋅10−8/9.7⋅10−5=1.3⋅10−4 M/s.
Answer: 1.3⋅10−4 M/s.
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