Question

Given that the molar volume change on melting ice is -1.56 cm3
mol -1,the molar enthalpy of fusion is 6.030 kJ mol-1, and the melting temperature of ice at atmospheric pressure (105 Pa) is 273.15 K,
calculate the melting temperature of ice at a pressure of 7 MPa.

Answer 1

Answer on Question #77171 - Chemistry - Physical Chemistry

Question:

Given that the molar volume change on melting ice is -1.56 cm³

mol -1, the molar enthalpy of fusion is 6.030 kJ mol-1, and the melting temperature of ice at atmospheric pressure (105 Pa) is 273.15 K,

calculate the melting temperature of ice at a pressure of 7 MPa.

Solution:

$$\ln \left(\mathrm {P} _ {2} / \mathrm {P} _ {1}\right) = \Delta \mathrm {H} / \mathrm {R} ^ {*} \left(1 / \mathrm {T} _ {1} - 1 / \mathrm {T} _ {2}\right)$$ $$(1 / T _ {1} - 1 / T _ {2}) = \ln (P _ {2} / P _ {1}) ^ {*} R / H$$ $$(1 / T _ {1} - 1 / T _ {2}) = 11.107 * 8.314 / 6030 = 0.0153$$ $$1 / T _ {2} = 1 / T _ {1} - 0.0153$$ $$1 / T _ {2} = 0.01164$$ $$T _ {2} = 85.91 \mathrm{~K}.$$

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