Question

if al3+ replaces na+ ions at the edge center of nacl lattice THEN CALCULATE THE VACANCIES IN 1 MOLE OF NACL

Answer 1

Answer on Question #76462 - Chemistry - Physical Chemistry

Question:

if al3+ replaces na+ ions at the edge center of nacl lattice THEN CALCULATE THE VACANCIES IN 1 MOLE OF NACL

Solution:

Since there are 1 units of NaCl in each cell, there are 3 Na + ions in the edge centers. So, 1 Al³⁺ will replace 3 Na⁺ ions. 3/4 moles of Na⁺ will replace by 1/4 mol Al³⁺ (for electrically neutral), and the residual Na⁺ ions in the crystal are 1/4 moles. Therefore, in the crystal, 1/2 of the mole of the lattice sites will occupy 1/2 moles (1/4 moles of Al³⁺ + 1/4 moles of Na⁺) cations, so the vacant sites:

1/2 mol = 1/2 * 6.02 * 10²³ = 3.0125 * 10²³.

Answer: 3.0125 * 10²³.

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