Answer to Question #75436 in Physical Chemistry for James

Question

When 2.00 g methane are burned in a bomb calorimeter (heat capacity = 2.677 x 103 J/K), the temperature rises from 24.00 oC to 27.08 oC. The amount of heat, q, in kJ absorbed by the calorimeter apparatus is ?

a) -(2.677 x 10^3)(3.08)
b) (2.677 x 10^3)(3.08)
c) (2.677 x 10^3)(24.00 - 27.08)
d) (2.677 x 10^3)(3.08)/1000
e) -(2.677 x 10^3)(3.08)/1000

Answer 1

Answer: a) and e) are wrong as the apparatus gains the energy! c) is wrong as T2 corresponds to 27.08, T1 to 24.00! b) is wrong as we should get the result in kJ
So the best answer is d!