Answer to Question #74426 in Physical Chemistry for sofi hadiya

Question #74426

The active mass of 7.0 g nitrogen in a 2.0 l container would be

Expert's answer

Solution:
Moles of N2 = m/M = 7/28 = 0.25 mol
Active mass = concentratione in mol ( L-1)
Active mass = 0.25 mol / 2 L = 0.125 mol/L.
Answer: 0.125 mol/L.

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