Answer to Question #68921 in Physical Chemistry for DEEPENDRA SINGH

Question

3.18 mole is situated in amoniam phashphet .what is the number of mole of oxygen in it compound?

Answer 1

n((NH4)3PO4) = 3.18 mole;

M((NH4)3PO4) = 149 g/mole
n((NH4)3PO4) = 3.18 mole

M(O) = 64 g/mole
n(O) = x mole

x = 64 * 3.18 / 149 = 1.37 mole
Answer: n(O) = 1.37 mole.