Question #67069

The half-life of a radioactive element with mass number 234 g is 2.5 x 105 years. How long after the isolation of a sample of this isotope will only one-six of the original mass be left?
1

Expert's answer

2017-04-08T11:09:07-0400

Answer on Question #67069 - Chemistry - Physical Chemistry

Question:

The half-life of a radioactive element with mass number 234g234\mathrm{g} is 2.5×1052.5 \times 10^{5} years. How long after the isolation of a sample of this isotope will only one-six of the original mass be left?

Solution:

The reactions of radioactive decay are related to first-order reactions.

For a first-order reaction, the half-life is defined as: t1/2=ln2kt_{1/2} = \frac{\ln 2}{k}.

The kinetic equation for the first-order reaction has the form: k=1tln[X]0[X]k = \frac{1}{t} \cdot \ln \frac{[X]_0}{[X]},


t=ln[X]0[X]k=ln[X]0[X]t1/2ln2=ln234392.5105ln2=447939.870.69=649188 years6.5105 years.t = \frac {\ln \frac {[ X ] _ {0}}{[ X ]}}{k} = \frac {\ln \frac {[ X ] _ {0}}{[ X ]} t _ {1 / 2}}{\ln 2} = \frac {\ln \frac {2 3 4}{3 9} \cdot 2 . 5 \cdot 1 0 ^ {5}}{\ln 2} = \frac {4 4 7 9 3 9 . 8 7}{0 . 6 9} = 6 4 9 1 8 8 \text{ years} \approx 6. 5 \cdot 1 0 ^ {5} \text{ years}.


Answer: 6.5×1056.5 \times 10^{5} years.

Answer provided by www.AssignmentExpert.com


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS