the ionization energy of hydrogen atom is 13.6 eV. The kinetic energy of the electron in hydrogen atom is a) 13.6 ev B0 31.6 eV C) 6.8 eV D0 21.7 eV
1
Expert's answer
2012-02-23T09:41:47-0500
The energy of the electron in the nth Bohr orbit is En=-Z2*Rch/n2 Given, ionization energy of hydrogen atom = Rch=13.6 eV. Therefore, En=-(13.6 eV)*Z2/n2. Kinetic& energy of the electron in the first Bohr orbit is E1=-13.6 eV. The answer is a)13.6 eV
Comments
Leave a comment