Answer to Question #61130 in Physical Chemistry for Amit Sharma

Question

At 298 K, a 0.100 M solution of acetic acid is 1.34% ionised. Calculate the ionisation
constant of acetic acid.

Answer 1

Ka = ɑ^2*C/(1 - ɑ); ɑ = 1.34% or 0.0134; C = 0.1 M.
Ka = 0.01342 × 0.1 / (1 - 0.0134) = 1.8 × 10^{-5}.
Answer: 1.8 × 10^{-5}.