What is Eo for the cell Ag l AgBr(s) I Br- (a1), Fe3+ (a2), Fe2+ (a3) l Pt . Given : Standard half-cell reduction potentials as
AgBr l Ag, (Eo)1/2 = 0.0713 V, Fe3+ l Fe2+, (Eo)1/2 = 0.771 V.
If a1 = 0.34, a2 = 0.1 & a3 = 0.02, then find Q, the reaction Quotient is Q = 0.588. Hence find E for the cell.
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