Question

How many Joules are required to convert 65 grams of ice at -10 degrees C to steam at 120 degrees C?
a. about 357 kiloJoules
b. about 100 kiloJoules
c. about 150 kiloJoules
d. about 175 kiloJoules
e. about 200 kiloJoules

Answer 1

Q=c*m*(t1-t0)+L*m+r*m=171KJ

c=4218
L=335000
r=2256000