Question #48241, Chemistry, Physical Chemistry
The plunger of a syringe is pulled out until the volume of air in the syringe is 30.0 mL at a pressure of 694 mm Hg. A stopper is then placed on the syringe so that no air can escape. What will be the air pressure inside the syringe if the plunger is depressed until the volume in the syringe is 26.0 mL?
Answer:
V₁ = 30.0 mL
V₂ = 26.0 mL
P₁ = 694 mm Hg
P₂ - ?
pV = nRT
n = const
R = const
if this is an isothermal compression process, then
T = const
pV = const
p₁V₁ = p₂V₂
p₂ = p₁*V₁/V₂
p₂ = 694*30/26 = 800.76 mm Hg
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