Question

Molybdenum at 20'C is BCC and has an atomic radius of 0.143 nm. calculate a value for its lattice constant a in nanometer.

Answer 1

Question:

Molybdenum at $20^{\circ}\mathrm{C}$ is BCC and has an atomic radius of 0.143 nm. Calculate a value for its lattice constant a in nanometer.

Solution:

For BCC:

$$\sqrt{3} \times a_0 = 4\,\mathrm{r},\ \mathrm{thus}$$ $$a_0 = \frac{4\,\mathrm{r}}{\sqrt{3}} = \frac{4 \times 0.143\,\mathrm{nm}}{\sqrt{3}} = 0.33\,\mathrm{nm}$$