What is the density of helium gas at 25 degree celsius and 760 torr?
R= 0.082 Lxatm/molxk
AW= 4 g/mole
a) 0.16 g/L
b) 6.1 g/L
c) 124 g/L
d) 0.082 g/L
1
Expert's answer
2014-06-18T09:04:25-0400
According to the ideal gas law, PV = nRT n = m/M - number of moles d = m/V - density Hence, P = (m/MV)RT PM = dRT d = PM/RT 760 torr = 1 atm d = (1 atm x 4 g/mol)/(0.082 Lxatm/molxK x 298 K) = 0.164 g/L So, the correct option is (a): 0.16 g/L
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Dear Muhammad ilyas khan please post a new question
Find out the density of helium gas as 250°C and 1000 torr.
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