Answer to Question #37239 in Physical Chemistry for radhika bauskar

Question

If 0.5 mole of BaCl2 is mixed with0.2 mole of Na3PO4 the maximum number of mole Ba3(PO4)2 that can be formed is?

Answer 1

Reaction:
3BaCl2 + 2Na3PO4 = Ba3(PO4)2 + 6NaCl

The mole ratio between BaCl2 and Na3PO4 is
n(BaCl2):n(Na3PO4)=3:2

The ratio of these compounds in the given mixture is 0.5/0.2 = 5:2 > 3:2.
Hence the BaCl2 is in excess and the Na3PO4 is the limiting reactant. The 1 mole of Ba3(PO4)2 occurs for each two moles of Na3PO4, hence the amount of Ba3(PO4)2

n[Ba3(PO4)2] = 1/2 * 0.2 = 0.1 mol.