Given that Zn/Zn2+(1M)//Cu2+(1M)/Cu
(a) calculate the emf of the cell
(b) predict if the reaction is spontaneous or non spontaneous
Given that Zn/Zn2+ E=0.34V, Cu2+/Cu E=1.10V
E=0.33+0.76=1.09 , it will be spontaneous since G=-nFE, and our case is positive E, G - is negative
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