Question #34511

Integral enthalpy of a solution of KCl when 1 mole of it is dissolved in 20 mole water is +15.90kJ. when 1 mole of it is dissolved in 200 mole water, the change in enthalpy is 15.58kJ. Calculate the enthalpy of hydration.

Expert's answer

The enthalpy of hydration is the change in enthalpy, when a solution containing 1 mole of a solute is diluted from one concentration to another.
dH hyd = 18.58 - 15.90 = 2.68 kJ
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