Integral enthalpy of a solution of KCl when 1 mole of it is dissolved in 20 mole water is +15.90kJ. when 1 mole of it is dissolved in 200 mole water, the change in enthalpy is 15.58kJ. Calculate the enthalpy of hydration.
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Expert's answer
2017-06-21T08:56:13-0400
The enthalpy of hydration is the change in enthalpy, when a solution containing 1 mole of a solute is diluted from one concentration to another. dH hyd = 18.58 - 15.90 = 2.68 kJ
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Dear Syed, we have checked the solution, it is correct.
It is wrong U have taken wrong data in solution
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