Question #33455

Hi! I am doing an experiment where I measure the volume of hydrogen gas produced from reacting different concentrations of an acid with a magnesium strip.

I have calculated the rate of reaction fir each concentration and the units are dm3s-1

I now need to plot a graph of concentration of the acid against rate of reaction.

Do I need to convert the units from dm3s-1 to moldm-3s-1 in order to determine the order of the reaction with respect to the acid?


Thanks :)

Expert's answer

Hi! I am doing an experiment where I measure the volume of hydrogen gas produced from reacting different concentrations of an acid with a magnesium strip. I have calculated the rate of reaction for each concentration and the units are dm3⋅s−1dm^3 \cdot s^{-1}. I now need to plot a graph of concentration of the acid against rate of reaction. Do I need to convert the units from dm3⋅s−1dm^3 \cdot s^{-1} to mol⋅dm−3⋅s−1mol \cdot dm^{-3} \cdot s^{-1} in order to determine the order of the reaction with respect to the acid?

Solution

Determine the reaction rate to the following formula


V=k⋅CV = k \cdot C


V-reaction rate; mol⋅dm−3⋅s−1mol \cdot dm^{-3} \cdot s^{-1}

K - Reaction rate constant; s−1s^{-1}

C - Concentration; mol⋅dm−3mol \cdot dm^{-3}

If you multiply the value of right side of equation, you get mol⋅dm−3⋅s−1mol \cdot dm^{-3} \cdot s^{-1}. On this basis, left side of equation must be mol⋅dm−3⋅s−1mol \cdot dm^{-3} \cdot s^{-1}

Answer: Yes, You need to convert the units from dm3⋅s−1dm^3 \cdot s^{-1} to mol⋅dm−3⋅s−1mol \cdot dm^{-3} \cdot s^{-1}

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