1. The volume sample of gas is 750 mL at 60°C and 0.7 atm. At what temperature will the sample 1.75 L occupy under a pressure of 1.80 atm?
Ideal gas law: "p*V=n*R*T"
Where p is pressure, V is volume, n is the amount of gas, R is ideal gas constant and T is temperature
R and n remain constant, which means "\\dfrac{p*V}{T}=constant"
Hence, "\\dfrac{p_1*V_1}{T_1}=\\dfrac{p_2*V_2}{T_2}"
"p_1 =0.7\\ atm,\\ p_2 =\\ 1.80\\ atm"
"V_1=750\\ ml,\\ V_2=1750\\ ml"
"T_1 =60^oC=60+273.15=333.15K"
"\\dfrac{0.7*750}{333.15}=\\dfrac{1.80*1750}{T_2}" ,
"T_2 = 1998.9K=1998.9-273.15=1725.75^oC"
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