Calculate the standard enthalpy of formation per mole of ZnS(s).
ZnS(s) + O2(g) → ZnO(s) + SO2(g) ΔH = −878.2 kJ
ΔHfo(ZnO(s)) = −348.3 kJ/mol
ΔHfo (SO2(g)) = −296.8 kJ/mol
Standard enthalpy of formation per mole of ZnS(s)=233.1kJ/mol
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