Answer to Question #322834 in Physical Chemistry for Vikram

Question #322834

Calculate the 1) average speed, 2) root mean square speed and, 3) most probable speed of oxygen molecules at 515k. (Given Mm(O2)=0.016kgmol^-1).

1
Expert's answer
2022-04-04T17:10:08-0400

T = 515 K;

M(O2) = 0.016 kg/mol = 16 g/mol;

R = 83140000 erg/(K * mol);

"\\pi" = 3.14;

1) The average speed: Saverage = ((8 * R * T)/("\\pi" * M))1/2 = ((8 * 83140000 * 515)/(3.14 * 16))1/2 = 82571 sm/sec = 825.71 m/sec;

2) The root mean square speed: Sroot mean square = ((3 * R * T)/(M))1/2 = ((3 * 83140000 * 515)/(16))1/2 = 89600 sm/sec = 896.00 m/sec;

3) The most probable speed: Smost probable = ((2 * R * T)/(M))1/2 = ((2 * 83140000 * 515)/(16))1/2 = 73158 sm/sec = 731.58 m/sec.

Answer: 1) 825.71 m/sec;

2) 896.00 m/sec;

3) 731.58 m/sec.


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