Answer to Question #319044 in Physical Chemistry for Sir mencho

Question

In a hittorf experiment ,a student electrolyzed aqueous AgNO3 solution using silver electrodes . The amount of AgNO3 in the anode compartment before electrolysis was 0.228g and the amount after electrolysis was 0.282g. during electrolysis it was found that 0.019g of copper was deposited in the copper colorimeter connected in series with the hittorf cell. Calculate the transport number of Ag+

Answer 1

W(Ag⁺)_{a, before} = 0.228 g;

W(Ag⁺)_{a, after} = 0.282 g;

$\Delta$ W(Ag)_k = 0.019;

Fall in concentration due to migration of Ag⁺: $\Delta$ W(Ag⁺)_a = W(Ag⁺)_{a, after} - W(Ag⁺)_{a, before} = 0.282-0.228 = 0.054 g;

Transport number of Ag⁺ : t(Ag⁺) = $\Delta$ W(Ag⁺)_k/$\Delta$ W(Ag⁺)_a = 0.019/0.054 = 0.352.

Answer: t(Ag⁺) = 0.352.