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Answer to Question #313012 in Physical Chemistry for ajoe

Question #313012

After being poured into a pan, 10.0 moles of water were heated on an electric stove. During this time, the temperature of the liquid rose from 26 ℃ to 38 ℃. How much heat, in J, was absorbed by the water? Use c = 73.32 J/mol K.

1
Expert's answer
2022-03-17T15:01:10-0400

"Q=cn\\Delta{T}=73.32\\frac{J}{mol\u00d7K}\u00d710.0\\ mol\u00d7(38\u00b0C-26\u00b0C)=8800\\ J"


Answer: 8800 J


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