Answer to Question #312823 in Physical Chemistry for jane

Question

Cisplatin or Platinol has a chemical PtCl2(NH3)2 that is used in the treatment of certain cancers. Calculate (a) the amount (mol) of compound in 285.3 g of cisplatin; (b) the number of hydrogen atoms in 0.98 mol of cisplatin.

Answer 1

M(cisplatin) = M(PtCl₂(NH₃)₂) = 300 g/mol;

If m(cisplatin) = 285.3 g

Then:

n(PtCl₂(NH₃)₂) = m(PtCl₂(NH₃)₂)/M(PtCl₂(NH₃)₂) = 285.3/300 = 0.951 moles;

N_a = 6.02 * 10²³ mol^-1;

If n(PtCl₂(NH₃)₂) = 0.98 mol

Then:

n(H) = 6 * n(PtCl₂(NH₃)₂) = 5.88 mol;

N(H) = n(H) * N_a = 5.88 * 6.02 * 10²³ = 35.4 * 10²³ = 3.54 * 10²⁴.

Answer: (a) 0.951 moles;

(b) 3.54 * 10²⁴.