Question

The equilibrium constant for the autoprotolysis of water, H2O (l) H+(aq) + OH−(aq), is Kw =

[H+][OH−] = 1.008 × 10−14 at 298 K. After a temperature-jump, the reaction returns to

equilibrium with a relaxation time of 3.7 x 10-5 s at 298 K and pH ≈ 7. Given that the forward

reaction is first-order and the reverse is second order overall, calculate the rate constants for the forward and reverse reactions.

Answer 1

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