How many molecules are in 5 moles of ammonia, NH3?
n(NH3) = 5 moles;
NA(Avogadro constant) = 6.02 * 1023 mol-1;
n = N/NA;
N(NH3) = n(NH3) * NA = 5 * 6.02 * 1023 = 30.1* 1023 = 3.01 * 1024 molecules.
Answer: 3.01 * 1024.
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