Answer to Question #299919 in Physical Chemistry for Ojasvee

Question #299919

2. 10.0 g of steam at 120.0 °C are converted into ice at -20.0°C.


a) Make a graph to indicate this change.


b) Calculate the total energy released (J) needed to do the problem above.




1
Expert's answer
2022-02-20T08:39:53-0500

Part 2a





Part2b



Specific heat capacity of Ice =2.093J/g/K=2.093J/g/K


Specific heat capacity of water =4.184J/g/K=4.184J/g/K


Latent heat of fusion of Ice =334J/g=334J/g


Latent heat of vaporization of water

2260J/g2260J/g


Specific heat capacity of steam

1.996J/g/K1.996J/g/K


Total energy released

=10[1.996×20+2260+4.184×100+334+2.093×20]=10[1.996×20+2260+4.184×100+334+2.093×20]


=3.094×104J=3.094×10^4J


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