Suppose 100ml of a 0.2 M ZnCl2 solution is mixed with 300ml of 0.1 KNO3. What is the pH?
ZnCl2 + KNO3
ZnCl2 = (100×0.2) = 20m mol
KNO3 = (300×0.1) = 30m mol
Total Volume= (100+300) = 400ml
Mk+ = (30÷400) = 0.075M
MNO3- = (30÷400)= 0.075M
MZn+ = (20÷400)= 0.05M
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