Assuming ideal solution behavior, what is the boiling point of a 033m solution of a nonvolatile solute in benzene?
ΔTb=kb.M\Delta T_b=k_b.MΔTb=kb.M
kb=2.53°cM−1k_b=2.53°cM^{-1}kb=2.53°cM−1
Boiling point of Benzene=80.1°c=80.1°c=80.1°c
Concentration =0.33M=0.33M=0.33M
ΔTb=2.53×0.33=0.8349°c\Delta T_b=2.53×0.33=0.8349°cΔTb=2.53×0.33=0.8349°c
Boiling point=80.1+0.8349=80.9349°c=80.1+0.8349=80.9349°c=80.1+0.8349=80.9349°c
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